This course explains the process of nuclear fission, focusing on the calculation of the mass defect (\(\Delta m\)) and the energy released from the fission of uranium-235 (U-235) after it absorbs a neutron. We will calculate the total energy released from 1 kg of U-235 using Einstein’s famous equation \(E = mc^2\).
Nuclear fission occurs when a heavy nucleus, such as uranium-235, absorbs a neutron and becomes unstable, leading to the splitting of the nucleus into two smaller nuclei (called fission products), along with the release of additional neutrons and a large amount of energy.
The general fission equation for U-235 when it absorbs a neutron is:
\[ \text{U}^{235} + \text{n} \rightarrow \text{Ba}^{141} + \text{Kr}^{92} + 3 \, \text{n} + \text{Energy} \]
Here, the fission products include the isotopes Ba-141 (Barium-141) and Kr-92 (Krypton-92), along with the release of 3 neutrons and energy.
The total mass before the fission (reactants) is greater than the total mass of the fission products. The difference in mass is called the mass defect, and this difference is converted into energy according to Einstein’s equation \(E = mc^2\).
The mass of the reactants consists of the mass of the U-235 nucleus and the neutron that is absorbed:
Using the approximate values:
The total mass of the reactants is:
The mass of the fission products includes the masses of Ba-141, Kr-92, and the 3 neutrons produced. Using the approximate masses:
The total mass of the products is:
The mass defect (\(\Delta m\)) is the difference between the mass of the reactants and the mass of the products:
Substituting the values:
Now, we convert the mass defect to energy using Einstein’s equation \(E = mc^2\), where:
First, we need to convert the mass defect from atomic mass units (u) to kilograms (kg). The conversion factor is:
Therefore, the mass defect in kilograms is:
Now, using \(E = mc^2\), the energy released is:
Thus, the energy released from one fission event is approximately \(2.78 \times 10^{-11} \, \text{J}\).
To find the total energy released from 1 kg of U-235, we first need to calculate the number of atoms in 1 kg of U-235:
Now, multiplying the energy per fission event by the number of atoms in 1 kg of U-235:
Therefore, the total energy released from **1 kg of U-235** undergoing fission is approximately **\(7.12 \times 10^{13} \, \text{J}\)**.
We have now calculated the mass defect and the energy released from the fission of a U-235 nucleus after it absorbs a neutron. The total energy released from 1 kg of U-235 is approximately \(7.12 \times 10^{13} \, \text{J}\), which is a massive amount of energy and highlights the power of nuclear fission as a source of energy in nuclear reactors and weapons.